How to split a force into a horizontal and a vertical part, and put it back together
Last updated 2026-09-25
Any force in a plane can be replaced by two forces at right angles, one horizontal (Fx) and one vertical (Fy), that together do exactly the same job. For a force F at angle θ from the horizontal, Fx = F·cos θ and Fy = F·sin θ. To go back, F = √(Fx² + Fy²).
A force has a size and a direction. The arrow shows both at once, but arrows are hard to add up. Numbers are easy.
So we ask two simpler questions instead:
Think of the force's shadow. With the sun straight overhead, the arrow's shadow on the ground is its horizontal component. With the light coming from the side, its shadow on a wall is the vertical component. The two shadows together describe the arrow completely.
The components replace the force; they don't add to it. Either you use the arrow, or you use its two components, never both.
Measure the angle θ from the horizontal:
Fx = F · cos θ
Fy = F · sin θ
Example: a 10 kN force, 30° above the horizontal, pointing right.
Fx = 10 × cos 30° = 8.66 kN
Fy = 10 × sin 30° = 5.00 kN
Notice that 8.66 + 5.00 isn't 10. Components don't add up to the force by simple addition; they add up the way the sides of a right triangle do.
The force is the hypotenuse of the triangle its components make:
F = √(Fx² + Fy²)
Example: Fx = 5 kN, Fy = −8 kN.
F = √(5² + 8²) = √89 = 9.43 kN
The size of the force always comes out positive. The direction comes from the signs of the components.
Truzme, like most statics textbooks, uses x to the right and y upward.
So −8 kN doesn't mean "negative force". It means 8 kN downward. Gravity loads are almost always a negative Fy.
In a truss, you rarely know angles. You know where the nodes are. A member that goes 3 m across and 4 m up is 5 m long, so a force along it splits the same way:
Fx = F × 35
Fy = F × 45
Across ÷ length and up ÷ length are just cos θ and sin θ, without ever working out θ. That's exactly how the support reactions example splits its 5 kN members into 3 kN and 4 kN.
In Truzme, each load and reaction is drawn as one arrow, and labelled with its two components instead of its size. A load labelled 5 kN and −8 kN pushes 5 kN to the right and 8 kN down.
It's labelled this way because that's how you use the numbers. Balance is checked one direction at a time:
ΣFx = 0
ΣFy = 0
To add forces, you add their components, x with x and y with y:
(5, −8) + (−2, 3) = (3, −5) kN
Adding the sizes (9.43 + 3.61) would give you a number that means nothing. If you do need the size of a force, work it out from the two components, as above. But the two numbers on the label are the ones that go into your equations.
Add a nodal load in Truzme and type its x and y values; the arrow follows. Set only y for a gravity load, or both for a load at an angle. The Getting started guide walks you through it.